概要信息：

¢›Ê š²ï>xÿþÉ>{§ÝXê
Xhè 1300011329
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¢žm2014c1230F
wžm2014c1231F
1 8‡¦
(1) 
)É>{§ÝDaì§ÝA5,¿ÿ½Ù§ÝXê
(2) 
)>{n‚{
(3) ÆSš²ï>xÿþ{
2 ¤ì^ä
ð6
,êi^L,ZX96.>{‡˜‡,êi§ÝO,>9,§,,‚,m'
3 ¢n
3.1 É>{§ÝA5
30-100em,kCqª:
RT = R0(1 +A1T )
Ù¥A13.85× 10−3 ◦C−1
3.2 É>{§ÝXêÿþ
>´ãX㤫:
1
ùp'AÏ´æ^
n‚{,ùŒ±ŒÌ~>>{ÚåXÚØ.
,	·‚k:
Uout =
I0
2
R0A1∆T + U0
5¿3ÿþž‡¦^ð6
,­½I034mA.@o·‚kØ(½ÝO:
σA = A
√
(
σk
k
)2 + (
σI0
I0
)2 + (
σR0
R0
)2
4 ¢SN
UC§Ý,P¹ØӧݞUout.¿(ÜÙ¦êâ^¦{[܎ÑÉ>{§ÝX
êA1.
5 êâL‚
T (◦C) 0 25.6 40 55 70 85 100
Uout (V) 0.06 19.82 30.53 41.52 52.52 64.08 75.86
„k
RP = 100.2 Ω, I0 = 4.004 mA
2
6 êâ?n9(J
k = 0.753 mV/◦C, r = 0.99994
σk = k
√
1/r2 − 1
n− 2
= 0.004 mV/◦C
Ù{ˆþØ(½ÝOŽXe:
σI0 =
1√
3
(4.004× 0.5% + 0.004) mA = 0.01 mA
σR0 =
1√
3
(100× 0.1% + 0.2× 2%) Ω = 0.06 Ω
I0 ± σI0 = (4.00± 0.01) mA, R0 ± σR0 = (100.20± 0.06) Ω
Œ±OŽ
A1 =
2k
I0R0
= 3.74× 10−3 ◦C−1
σA1 = A1
√
(
σk
k
)2 + (
σI0
I0
)2 + (
σR0
R0
)2 = 0.02× 10−3 ◦C−1
A1 ± σA1 = (3.74± 0.03)× 10−3 ◦C−1
7 gK
(1) §ÝÿþØO(,KŒ.>ØLÖêkò´,KØŒ.ð6
kÅÄ,Ké. ¢æ
^
>{nà{.
(2) ù´ÏT = 0 ◦CžRP˜vk¦>x²ï. XJ l،{K´é,
Œ±Ñ.
3