上海大学通信试题2.pdf

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2004      
 
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_______ _________ ______ 
 
         
         
 
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1 2 3 4 5 6 7 8 
F F T F F F T F 
 
1   
2  
 
3   
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5  100kHz
101.5kHz 4kHz 96kHz  
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D C C B A B 
1 A 13 PCM  
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6 PCM30/32 125­6 
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D A  
 
 
 
 
   








































 
 
13 A 01010110 
1    
1   
2     
 
1 C1=0  
       C2C3C4=101 6 256 
       C5C6C7C8=0110  256+6*16+16*0.5=360 
       -360  
    2 11 00101101000 
 
 
 
8 435 12  
1 3  
2 3  
3 m 3   
4 m 3  
 
1 435----100011101     
  x8+x4+x3+x2+1 
2 100011101 101110001  
  x8+x6+x5+x4+1 
3 n=8 m=2n-1=28-1=255 
4.  
 
 
 
 
 
 
 
 
 
 
 
                         
10 PCM 2 320 kbit/s
1.28Mbit/s 12                         
1.   PCM M  
2. ´  
3. B  
4. PCM Bmin   
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1 (8k*N)*10+2*320k=1280k 
       N=8 8  
       PCM M=28=256 
2 ´ 


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3 S2 (t) h2 (t) S20 ( t ) 2  
 
 
 
 
 
 
 
 
 
 
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7     ( 6 )       ( 5 )       ( 4 )       ( 3 )       ( 2 )      1
     
   
 
 
 
 
  
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S220(t) 
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0      T/2     T     3T/2      t

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